A metal salt with the formula MSO4 crystallizes from water to form a solid with the composition MSO4⋅5H2O. At 298 K, the equilibrium vapor pressure of water above this solid is 15.7 Torr.

MSO4⋅5H2O(s)↽−−⇀MSO4(s)+5H2O(g)
What is the value of ΔG for the reaction when the vapor pressure of water is 15.7 Torr?

Δ= ? J/mol

What is the value of Δ for the reaction when the vapor pressure of water is 571 Torr?

ΔG= ? J/mol

The value of Δ for the reaction when the vapor pressure of water is 571 Torr is as follows

Explanation:

At 298 K, the equilibrium vapor pressure of water above this solid is 28.5 Torr.

MSO4⋅5H2O(s)<> MSO4(s)+5H2O(g)

1 atm = 760 torr

thus, 28.5 torr= 0.0375 atm

Kp = [p(H2O)]5 = ( 0.0375)5 = 7.42 into 10-8

What is the value of Δ for the reaction when the vapor pressure of water is 28.5 Torr?

we have, Δ = - RT ln K

in this case K = Kp

Δ = - (8.314 J by K-mol into 298) ln 7.42 into 10-8 = + 40.673 kJ/mol

What is the value of Δ for the reaction at this temperature if the vapor pressure of water is 533 Torr?

533 torr= 0.701 atm

Kp = [p(H2O)]5    = ( 0.701)5 = 0.1697

Δ = - (8.314 J by K-mol into 298) ln 0.1697 = + 4.395 kJ/mo

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explanation: a formula which shows the arrangement of atoms in the molecule of a compound

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.