A food substance kept at 0°C becomes rotten (as determined by a good quantitative test) in 8.3 days. The same food rots in 10.6 hours at 30°C. Assuming the kinetics of the microorganisms enzymatic action is responsible for the rate of decay, what is the activation energy for the decomposition process? Hint: Rate varies INVERSELY with time; a faster rate produces a shorter decomposition time. 1.67.2 kJ/mol 2.2.34 kJ/mol 3.23.4 kJ/mol 4.0.45 kJ/mol

1.   67.2 kJ/mol

Explanation:

Using the derived expression from Arrhenius Equation

Given that:

time = 8.3 days = (8.3 × 24 ) hours = 199.2 hours

time = 10.6 hours

Temperature = 0° C = (0+273 )K = 273 K

Temperature = 30° C = (30+ 273) = 303 K

Rate = 8.314 J / mol

Since

Then we can rewrite the above expression as:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

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explanation: