What is the mass of sulfuric acid in 50.0 mL of a 6.00 M solution?

The answer to your question is 29.4 grams of H₂SO₄

Explanation:

Data

mass of sulfuric acid

volume = 50 ml

Molarity = 6 M

Process

1.- Write the formula of Molarity

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 6 x 0.05

-result

moles = 0.3

2.- Calculate the molar mass of Sulfuric acid

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4) = 2 + 32 + 64 = 98 g

3.- Calculate the mass in the solution

                 98 g of H₂SO₄ 1 mol

                    x                   0.3 moles

                            x = (0.3 x 98) / 1

                            x = 29.4 grams of H₂SO₄

they both have a y in them

explanation: