A chemist has a 2.0 M solution of copper (II) sulfate. Is he takes 400 mL of this solution and dilutes it with 1200 mL of water, which of the following would be the most accurate calculation of the molarity of the new solution?

0.66 M is the accurate molarity of the new solution of volume of 1200 ml.

Explanation:

Data given:

molarity of copper(II) sulphate, Mconc.= 2M

volume of 2M solution taken Vconc. = 400 ml

volume taken for dilution, Vdilute = 1200 ml

molarity of the diluted solution, Mdilute =?

We will use the formula for dilution as

Mconc Vconc = Mdilute x V dilute  (conc is concentrated)

putting the values in the equation:

2 x 400 = Mdilute x 1200

Mdilute =

   Mdilute  = 0.66 M

When the solution is diluted to the volume of 1200 ml its molarity changes to 0.66 M.

answer; i believe the correct answer is (solid gold);

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons