What is the molarity of a solution of hcl if 250 ml of a 0.50 m solution of naoh will completely neutralize 100.ml of this acid

The molarity of the acid is 1.25 M.

Explanation:

We have to find the molarity of HCl by writing the balanced equation that is the neutralization reaction of Hydrochloric acid with the base, Sodium Hydroxide, NaOH.

HCl + NaOH → NaCl + H₂O

From the balanced equation, we can find that one mole of an acid is used to neutralize one mole of a base.

As per the law of volumetric analysis, we can write the equation as,

V1M1 = V2M2

Here V1 and M1 being the volume and molarity of the NaOH

V2 and M2 being the volume and molarity of HCl

V1 = 250 ml

M1 = 0.50 M

V2 = 100 ml

M2 = ?

Now the above equation can be rearranged to find the molarity of the acid as,

M2 =

    =

     = 1.25 M

So the molarity of the acid is 1.25 M.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol