CaCO3 + 2HCl --> CaCl2 + CO2 + H2O What mass of carbon dioxide is produced when 21 moles of HCl reacts with excess calcium carbonate?

The answer to your question is 462 grams

Explanation:

Data

mass of CO₂ = ?

moles of HCl = 21

Balanced chemical reaction

                CaCO₃  +  2HCl   ⇒   CaCl₂  +  CO₂  +  H₂O

Process

1.- Calculate the moles of CO₂ produced using proportions

                      2 moles of HCl 1 mol of CO₂

                     21 moles of HCl  x

                                       x = (21 x 1) / 2

                                       x = 21 / 2

                                       x = 10.5 moles of CO₂

2.- Calculate the molar mass of CO₂

CO₂ = 12 + (16 x 2) = 12 + 32 = 44 g

3.- Convert the moles of CO₂ to grams

                         44 g of CO₂ 1 mol

                           x                 10.5 moles

                                   x = (10.5 x 44) / 1

                                   x = 462 grams

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b) mutualism

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