2al+6hbr -> 2albr3+3h2. when 3.22 moles of al reacts with 4.96 moles of hbr, how many moles of h2 are formed?

2 Al+6 HBr =  2 AlBr₃ + 3 H₂

2 moles Al  6 moles HBr 3 moles H₂
3.22 moles Al 4.96 moles HBr ( moles H₂ )

moles H₂ = 4.96 x 3 / 6

moles H₂ = 14.88 / 6

= 2.48 moles of H₂

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