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Chemistry, 18.04.2020 10:07 Destine1965

Use this information to calculate AGxn
2C_H2(g)+50 (9) — 4C02(g)+ 2H20(9)
AG CHą = 209.2 kJ/mol
AGE. CO. = -394.4 kJ/mol
AG 4,0 = -228.57 kJ/mol
TELE
ebo..
AGx =
kJ

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You know the right answer?
Use this information to calculate AGxn
2C_H2(g)+50 (9) — 4C02(g)+ 2H20(9)
AG CHą = 209.2...

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