Determine the solubility product of potassium hydrogen tartrate (KHT).

A saturated KHT solution was prepared by adding solid KHT to a beaker containing
70.0 mL of 0.010M NaCl and 30.0 mL of 0.01M KCl., [NaCl] = 0.070 M, [KCl] = 0.030 M

The solution was stirred for 20 minutes.
The following equilibrium resulted: KHT(s) K1+(aq) + HT1-(aq)
The saturated solution was then filtered. There was some solid KHT left behind in the beaker.

35.0 mL of the filtered solution was titrated with 0.0502M NaOH solution.
18.50 mL of NaOH was needed to reach the end point of the titration.

The molar mass of KHT = 188 grams / mole.
(1pts)
Question 39 - Determine the solubility product of potassium hydrogen tartrate (KHT). A saturated KHT solution was prepared by adding solid KHT to a beaker containing 70.0 mL of 0.010M NaCl and 30.0 mL of 0.01M KCl., [NaCl] = 0.070 M, [KCl] = 0.030 MThe solution was stirred for 20 minutes.
The following equilibrium resulted:
KHT(s) K1+(aq) + HT1-(aq) The saturated solution was then filtered.
There was some solid KHT left behind in the beaker.
35.0 mL of the filtered solution was titrated with 0.0502M NaOH solution.
18.50 mL of NaOH was needed to reach the end point of the titration.
The molar mass of KHT = 188 grams / mole.

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