If the temperature of the helium balloon were increased from 30°C to 35°C and the volume of the balloon only expanded from 0.47L to 1.55L, how much pressure would be inside the balloon?

Explanation:

To solve this problem, we can use the Combined Gas Laws:

Data:

p₁ = p₁; V₁ = 0.47 L; n₁ = n₁;  T₁ = 30 °C

p₂ = ?;  V₂ = 1.55 L; n₂ = n₁; T₂ = 35 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (30 + 273.15)K = 303.15 K

T₂ = (35 + 273.15)K = 308.15 K

(b) Calculate the new pressure

sure what is it? ^w^

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.