A 2.50 g sample of zinc is heated, and then placed in a calorimeter containing 65.0 g of water. Temperature of water increases from 20.00 oC to 22.50 oC. The specific heat of zinc is 0.390 J/g oC. Assuming no heat loss, what was the initial temperature of the zinc metal sample?

The initial temperature of the zinc metal is  720 ° C

Explanation:

Given data,

Zn

m=2.50 g            

C=0.390 J/g° C

ΔT= (22.50° C- Ti)

H2O

m= 65.0 g

C= 4.184 J/ g° C

ΔT = 2.50° C

We have the formula,

qH20= - qZn

(65.0 g) (4.184 J/ g° C) (ΔT 2.50° C)=(2.50 g) ( 0.390 J/g° C) (ΔT 22.50° C- Ti)

solving the equation we get,

697.3 ° C=- 22.50 ° C+Ti

Ti= 720 ° C

The initial temperature of the zinc metal is  720 ° C

ugh fiel iente of insistí is did kiwis jaj

elements make up everything, and they combine to make compounds.

the answer is c