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Chemistry, 17.04.2020 02:10 maybaby7545
From the following heats of combustion, CH3OH(l) + 3 2 O2(g) → CO2(g) + 2H2O(l) ΔH o rxn = −726.4 kJ/mol C(graphite) + O2(g) → CO2(g) ΔH o rxn = −393.5 kJ/mol H2(g) + 1 2 O2(g) → H2O(l) ΔH o rxn = −285.8 kJ/mol Calculate the enthalpy of formation of methanol (CH3OH) from its elements: C(graphite) + 2H2(g) + 1 2 O2(g) → CH3OH(l) kJ/mol
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From the following heats of combustion, CH3OH(l) + 3 2 O2(g) → CO2(g) + 2H2O(l) ΔH o rxn = −726.4 kJ...
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