What is the volume of the air in a balloon that occupies 8.7 L at 50.0°C if the temperature is lowered to 25.0°C?

8.03L

Explanation:

Given parameters:

Initial volume, V₁  = 8.7L

Initial temperature T₁  = 50°C , in Kelvin gives 50+273  = 323K

Final temperature T₂ = 25°C, in Kelvin gives 25 + 273  = 298K

Unknown:

Final volume V₂  = ?

Solution:

Since we are dealing with volume and temperature relationships under constant pressure, we simply apply the Charles's law.

Charles's law states that "the volume of a given mass of gas is directly proportional to the temperature provided the pressure remains constant".

Mathematically, we have;

where V andV T are volume and temperature, 1 and 2 are initial and final states.

Input the parameters and solve for V₂;

          V₂  = 8.03L

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2