Chemistry, 16.04.2020 01:52 rafamoreura
A mixture of NaBrO 3 , NaBrO3, NaHCO 3 , NaHCO3, Na 2 CO 3 , Na2CO3, and NaBr NaBr was heated, producing H 2 O , H2O, CO 2 , CO2, and O 2 O2 gases by the following equations. 2 NaBrO 3 ( s ) ⟶ 2 NaBr ( s ) + 3 O 2 ( g ) 2NaBrO3(s)⟶2NaBr(s)+3O2(g) 2 NaHCO 3 ( s ) ⟶ Na 2 O ( s ) + H 2 O ( g ) + 2 CO 2 ( g ) 2NaHCO3(s)⟶Na2O(s)+H2O(g)+2CO2(g) Na 2 CO 3 ( s ) ⟶ Na 2 O ( s ) + CO 2 ( g ) Na2CO3(s)⟶Na2O(s)+CO2(g) If 124.5 g 124.5 g of the mixture produces 1.83 g 1.83 g of H 2 O , H2O, 15.51 g 15.51 g of CO 2 , CO2, and 2.87 g 2.87 g of O 2 , O2, what was the mass of each compound in the mixture? Assume complete decomposition of the mixture. NaBr NaBr does not react under the reaction conditions. mass of NaBrO 3 : NaBrO3: g mass of NaHCO 3 : NaHCO3: g mass of Na 2 CO 3 : Na2CO3: g mass of NaBr : NaBr: g
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Chemistry, 21.06.2019 23:00, fastpitchhailey1354
An electrons position cannot be known precisely only it's probability of being in a certain location can be known
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A mixture of NaBrO 3 , NaBrO3, NaHCO 3 , NaHCO3, Na 2 CO 3 , Na2CO3, and NaBr NaBr was heated, produ...
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