A student prepares a aqueous solution of 4chlorobutanoic acid . Calculate the fraction of -chlorobutanoic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to significant digits.

Incomplete question: The concentration of the aqueous solution is 0.65 mM

The percentage of dissociation is 19.23%

Explanation:

The pKa of the 4-chlorobutanoic acid is 4.53, thus:

The initial concentration is 0.65 mM = 6.5x10⁻⁴M

The reaction is:

                   HA        +         H₂O        =         H₃O⁺        +         A⁻

I                6.5x10⁻⁴                                          0                       0

C               -x                                                   +x                      +x

E              6.5x10⁻⁴ -x                                      x                        x

The Ka is:

The percentage of dissociated is:

%

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.