If 354.2g PbCl2 are reacted with excess Na3PO4, how many grams of NaCl will be produced

The mass of produced is, 149 grams.

Explanation : Given,

Mass of = 354.2 g

Molar mass of = 278 g/mol

Molar mass of = 58.5 g/mol

First we have to calculate the moles of

Now we have to calculate the moles of

The balanced chemical equation is:

From the reaction, we conclude that

As, 3 moles of react to give 6 mole of

So, 1.27 moles of react to give mole of

Now we have to calculate the mass of

Therefore, the mass of produced is, 149 grams.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2