A student ran the following reaction in the laboratory at 1089 K: 2SO3(g) 2SO2(g) + O2(g) When she introduced 8.39×10-2 moles of SO3(g) into a 1.00 liter container, she found the equilibrium concentration of O2(g) to be 1.78×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.

The equilibrium constant, Kc is 0.00967

Explanation:

Step 1: Data given

Temperature = 1089 K

Number of moles SO3 = 8.39 * 10^-2 moles = 0.0839 moles

Volume = 1.0 L

The equilibrium concentration of O2(g) to be 1.78* 10^-2 M

Step 2: The balanced equation

2SO3(g) ⇆ 2SO2(g) + O2(g)

Step 3: The initial concentration

Concentration = moles / volume

[SO3] = 0.0839 moles / 1 L = 0.0839 M

[SO2] = 0M

[O2] = 0M

Step 4: The concentration at equilibrium

For 2 moles SO3 we'll have 2 moles SO2 and 1 mol O2

[SO3] = 0.0839 - 2X M

[SO2] = 2X M

[O2] = XM = 1.78 * 10^-2 M = 0.0178 M

So X = 0.0178

[SO3] = 0.0839 - 2*0.0178 = 0.0483 M

[SO2] = 2*0.0178 = 0.0356 M

[O2] = XM = 1.78 * 10^-2 M = 0.0178 M

Step 5: Calculate the equilibrium constant, Kc

Kc = [O2][SO2]² / [SO3]²

Kc = (0.0178 * 0.0356²)/0.0483²

Kc = 0.00967

The equilibrium constant, Kc is 0.00967

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.