Chemistry, 15.04.2020 03:02 beauburgess1108

Based on the following thermochemical equations, what is the heat of vaporization of titanium(IV) chloride?
Ti(s) + 2 Cl2(g) →
TiCl4(l)
ΔH = –804.2 kJ/mol
TiCl4(g) → 2 Cl2(g) +
Ti(s)
ΔH = 763.2 kJ/mol

Answers: 1

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Based on the following thermochemical equations, what is the heat of vaporization of titanium(IV) chloride? Ti(s) + 2 Cl2(g) → TiCl4(l) ΔH = –804.2 kJ/mol TiCl4(g) → 2 Cl2(g) + Ti(s) ΔH = 763.2 kJ/mol

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Other questions on the subject: Chemistry

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Based on the following thermochemical equations, what is the heat of vaporization of titanium(IV) chloride?
Ti(s) + 2 Cl2(g) →
TiCl4(l)
ΔH = –804.2 kJ/mol
TiCl4(g) → 2 Cl2(g) +
Ti(s)
ΔH = 763.2 kJ/mol