One problem with elimination reactions is that mixtures of products are often formed. For example, treatment of 2-bromo-2-methylbutane with KOH in ethanol yields a mixture of two alkene products. What are their likely structures?

Structures are given below.

Explanation:

Treatment of 2-bromo-2-methylbutane with KOH in ethanol will give elimination of HBr through E2 mechanism.H atoms adjacent to Br will be eliminated.2-bromo-2-methylbutane has two possible adjacent H atoms that can be eliminated giving mixture of products.Product of this elimination reaction is alkene. Here saytzeff fule is followed during elimination. So most substituted alkene will be major product.Structure of alkenes are given below.

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Answer246 k;