7.47 Two atoms have the electron configurations 1s22s22p6 and 1s22s22p63s1. The first ionization energy of one is 2080 kJ/mol and that of the other is 496 kJ/mol. Match each ionization energy with one of the given electron configurations.

2080 kJ/mol is the first ionization of 1st atom and 496 kJ/mol is the first ionization of 2nd atom

Explanation:

Given electronic configurations are :

1st:

2nd :

given 1st ionization energy are: 2080 kJ/mol and 496 kJ/mol

generally ionization energy of fulfilled orbital is more than half filled orbital and these two state are more stable.

therefore ionization energy of fulfilled is more than half filled orbital

hence

ionization energy of 1st atom will be very high because its orbital is fulfilled and less energy for 2nd atom so 2080 kJ/mol is the first ionization of 1st atom and 496 kJ/mol is the first ionization of 2nd atom.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

2b2t

explanation:

2b2t