What is the slow, rate-determining step, in the acid-catalyzed dehydration of 2-methyl-2-propanol?
H2SO4
(CH3)3COH →
a. Protonation of the alcohol to form an oxonium ion.
b. Loss of water from the oxonium ion to form a carbocation.
c. Loss of a β-hydrogen from the carbocation to form an alkene.
d. The simultaneous loss of a β-hydrogen and water from the oxonium ion.
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