The quantum yield of light-induced chemical reactions (called photochemical reactions) measures the efficiency of the process. The quantum yield, ϕ, is defined as:
ϕ = number of reaction events number of photons absorbed.
Suppose a quantum yield for the reaction CH3X > CH3 + X is ϕ = 0.26. A cuvette containing a solution of CH3X is irradiated with 280-nm with a power of 885 mW for 10.0 minutes.
(A) Assuming total absorption of the light by the sample, what is the maximum amount (in moles) of CH3X that breaks apart?Express your answer to two significant figures.

1.9×10^20

Explanation:

ϕ = number of reaction events /number of photons absorbed

ϕ= 0.26

Energy= power× time

885×10^-3×10×60= 531J

But E= nhc/λ

n= number of photons

h= planks constant

c= speed of light

λ= wavelength

n= Eλ/hc

n= 531×280×10^-9/6.6×10^-34 ×3×10^8

n= 7.5×10^20

Therefore

From

ϕ = number of reaction events /number of photons absorbed

Number of reaction events= 0.26×7.5×10^20

= 1.95×10^20

for points guys

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.