C3H2 + 502 + 3 CO2 + 4H20
6) Determine the number of moles of water produced from 1.55 moles of propane (CH3).

6.2 moles

Explanation:

C3H8(g) + 5O2(g) ---> 3CO2(g) + 4H2O(g)

The balanced equation above shows the combustion of propane, C3H8 in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O

The mole ratio of combustion are as follows:

1 mole of C3H8 react to produce 4 moles of H2O

1.55 mole of C3H8 will react to produce Z moles of H2O

To get the value of Z, cross multiply

Z x 1 mole = 1.55 mole x 4 mole

Z = 6.2 moles

Thus, 6.2 moles of water will be produced from 1.55 moles of propane

the volume increases

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