How many moles of Fe2O3 will be produced from 27.0g of Fe assuming O2 is available in excess

0.24 moles of Fe2O3 will be produced from 27.0g of Fe assuming O2 is available in excess.

Explanation:

Data given:

mass of Fe = 27 grams  

mass of oxygen = excess

moles of = ?

Atomic mass of Fe= 55.48 grams/mole

atomic mass of Fe2O3 = 159.69 grams/mole

moles of Fe given =0.48 moles

number of moles =

                               =

                                = 0.48 moles

Balanced chemical equation for the reaction is:

4 Fe + 3  ⇒ 2

4 moles of Fe gives 2 mole of Fe2O3

So, 0.48 moles will give x mole of Fe2O3

=

4x = 2 x 0.48

x =

x = 0.24 moles

so 0.24 moles of is formed from 27 grams of Fe.

the answer is b. dilution