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How many liters of water vapor would be produced in the combustion of 12.5L of ethane, C2H6 at STP?

The answer to your question is 37.5 l of water vapor

Explanation:

Data

volume of ethane = 12.5 l

volume of water vapor = ?

Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒   4CO₂  +  6H₂O

-Convert the volume of C₂H₂ to moles

                    1 mol of C₂H₂ 22.4 l

                    x                     12.5 l

                             x = (12.5 x 1) / 22.4

                             x = 0.56 moles

-Calculate the moles of water vapor

                 2 moles of C₂H₂ 6 moles of H₂O

                 0.56 moles of C₂H₂  x

                          x = (0.56 x 6) / 2

                          x = 1.67 moles of H₂O

-Calculate the volume of water vapor

                          22.4 l of H₂O 1 mol

                             x                   1.67 moles

                             x = (1.67 x 22.4) / 1

                             x = 37.5 l

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.