Chemistry, 10.04.2020 22:17 jobana

2C(s)+O2(g)2H2(g)+O2(g)H2O(l)→2CO(g )→2H2O(g)→H2O(g)ΔHΔHΔH=−222kJ=−484k J=+44kJ Use the thermochemical data above to calculate the change in enthalpy for the reaction below. H2O(l)+C(s)→CO(g)+H2(g)

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2C(s)+O2(g)2H2(g)+O2(g)H2O(l)→2CO(g )→2H2O(g)→H2O(g)ΔHΔHΔH=−222kJ=−484k J=+44kJ Use the thermochemic...

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