Question 5
Determine the mass (in g) of oxygen (Mc = 32.00) that occupies a volume of 146.7 cm? at a pressure of
106.5 kPa and a temperature of 167 °C. Give the answer to 3 significant figures
9

0.128 g

Explanation:

Given data:

Volume of gas = 146.7 cm³

Pressure of gas = 106.5 Kpa

Temperature of gas = 167°C

Mass of oxygen gas = ?

Solution:

Volume of gas = 146.7 cm³ (146.7 /1000 = 0.1467 L)

Pressure of gas = 106.5 Kpa (106.5/101 = 1.1 atm)

Temperature of gas = 167°C (167 +273.15 = 440.15 K)

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

n = PV/RT

n = 1.1 atm× 0.1467 L / 0.0821 atm.L/ mol.K   × 440.15 K

n = 0.1614 / 36.14 /mol

n = 0.004 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.004 mol × 32 g/mol

Mass = 0.128 g

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explanation:

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)