X^2+13x+30
How do I factor this?
will give brainiest

(x+10) (x+3)

Explanation:

1) this quadratic equation is in the form of: ax^2+bx+c

where we need to figure out what*what=c(30)

and what+what=13(b)

factors of 30:  -1,-30  1,30  2,15  -2,-15  3,10  -3,-10  5,6   -5,-6

factors of 30 which equal 13:    3,10

lets substitute 3 and 10 in lace of 13x to factor by grouping:

x^2+3x+10x+30

make two sets:

set a) x^2+3x

set b) 10x+30

the GCF in set a is "x":

x(x+3)

The Gcf in set b is 10:

10(x+3)

now combine the terms outside the parantheses:

(x+10)(x+3)=0

Hope this helps!

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g