The equilibrium constant is given for one of the reactions below. determine the value of the missing equilibrium constant.
2 hd(g) ⇌ h2(g) + d2(g)
kc = 0.28

6 h2(g) + 6 d2(g) ⇌ 12 hd(g)
kc = ?

a) 0.00048
b) 1.2
c) 1.62
d) 2075
e) 0.81

Given the original equation of 2 HD(g) ⇌ H2(g) + D2(g)  with Kc = 0.28 and asked for the kc of the equation 6 H2(g) + 6 D2(g) ⇌ 12 HD(g), we can see that the equation 1 is reversed and multiplide by 6. in this case, the reverse means kc is equal to 1/0.28 and that the multiplication by 6 raises the new kc to 6. the new kc is equal to D. 2075