A student prepares a aqueous solution of trimethylacetic acid . Calculate the fraction of trimethylacetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to significant digits.

The question is incomplete, here is the complete question:

A student prepares a 0.21 mM aqueous solution of trimethylacetic acid. Calculate the fraction of trimethylacetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to 3 significant digits.

The percent of dissociation of trimethylacetic acid is 19.5 %

Explanation:

We are given:

Concentration of trimethylacetic acid = 0.21 mM  = 0.00021 M    (Conversion factor:  1 mole = 1000 millimoles )

The chemical equation for the dissociation of trimethylacetic acid follows:

Initial:                   0.00021

At eqllm:             0.00021-x              x            x

The expression of for above equation follows:

We know that:

Putting values in above expression, we get:

Neglecting the negative value of 'x' because concentration cannot be negative.

To calculate the fraction of dissociation, we use the equation:

Putting values in above equation, we get:

Hence, the percent of dissociation of trimethylacetic acid is 19.5 %

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).