How much energy is absorbed with radiation of wavelength of 200 nm?

E = 0.09 × 10⁻¹⁷J

Explanation:

Given data:

wavelength of radiations = 200 nm (200× 10⁻⁹ m)

Energy absorbed = ?

Solution:

Formula:

E = hc/λ

h = 6.63× 10⁻³⁴ Js

c = 3 × 10⁸ m/s

Now we will put the values.

E = 6.63× 10⁻³⁴ Js × 3 × 10⁸ ms⁻¹  / 200× 10⁻⁹ m

E = 19.89 × 10⁻²⁶ J / 200× 10⁻⁹

E = 0.09 × 10⁻¹⁷J

може ли да зареждате повече информация, моля

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o