What is the net ionic equation for the reaction between aqueous solutions of na3po4 and cuso4?

3Cu²⁺ + 2PO₄³⁻ → Cu₃(PO₄)₂ (s)

Explanation:

Double displacement reaction: A chemical reaction in which aqueous solution of two salts react to give two products by exchanging their counterions.

The chemical equation for the chemical reaction between Na₃PO₄ (aq) and CuSO₄ (aq) is given as:

2 Na₃PO₄ (aq) + 3 CuSO₄ (aq) → Cu₃(PO₄)₂ (s) + 3 Na₂SO₄ (aq)

The full ionic equation for this chemical reaction is:

6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 3SO₄²⁻(aq) → Cu₃(PO₄)₂ (s) + 6Na⁺(aq) + 3SO₄²⁻(aq)

Therefore, the net ionic equation for this chemical reaction is:

3Cu²⁺ + 2PO₄³⁻ → Cu₃(PO₄)₂ (s)

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.

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