Sodium hydroxide reacts with aluminum and water to produce hydrogen gas:2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H2(g)What mass of hydrogen gas would be formed from a reaction of 1.33 g Al and 4.25 g NaOH in water?

0.147 grams

Explanation:

To calculate the moles :

According to stoichiometry :

2 moles of require = 2 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 2 moles of give = 3 moles of

Thus 0.049 moles of give =  of

Mass of

Thus 0.147 g of will be produced from the given masses of both reactants.