A solution of AgNO3 contains 29.66 g of solute in 100.0 mL of solution. What is the molarity of the solution

1.7 M

Explanation:

Given data:

Mass of AgNO₃ = 29.66 g

Volume of solution = 100 mL (100/1000 = 0.1 L)

Molarity of solution = ?

Solution;

Number of moles of AgNO₃:

Number of moles = mass/ molar mass

Number of moles = 29.66 g/ 169.87 g/mol

Number of moles = 0.17 mol

Molarity of solution:

Molarity =  moles of solute / volume of solution in L

Molarity = 0.17 mol / 0.1 L

Molarity = 1.7 M