Write the valence molecular orbital configuration of Ne2+. The fill order for Ne is as follows: σ2s σ*2s σ2p π2p π2p π*2p π*2p σ*2p What is the bond order of Ne2+ according to molecular orbital theory?

The valence molecular orbital configuration of Ne2+ is:

The bond order of Ne2+ according to molecular orbital theory is:  

According to the given question, we are asked to show the valence molecular orbital configuration of Ne2+ and also the bond order based on the molecular orbital theory.

As a result of this, we can see that Ne2^+ is supposed to have nineteen electrons and if the core electrons are displayed as KK, then the valence molecular orbital configuration would be KK σ2s2 σ*2s2 σ2p2 π2p2 π2p2 π*2p2 π*2p2 σ*2p1.

With this in mind, we would have to find the bond order which is given as 0.5(bonding- anti bonding) electrons which would give us 0.5 (1)= 0.5

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Valence orbital configuration of Ne2^+

σ2s2 σ*2s2 σ2p2 π2p2 π2p2 π*2p2 π*2p2 σ*2p1

Bond order= 0.5

Explanation:

Ne2^+ ought to have 19 electrons. If the inner or coire electrons of the molecule are shown as KK, then the full molecular orbital configuration of the molecule is

KK σ2s2 σ*2s2 σ2p2 π2p2 π2p2 π*2p2 π*2p2 σ*2p1

Hence the bond order is 1/2(bonding- anti bounding) electrons

Bonding electrons= 10

Anti bonding electrons= 9

1/2(10-9) = 0.5

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