Equation: SiO2 + 3C = SiC + 2CO When 90.0 g of silicon dioxide is heated with an excess of carbon, 41.0 g of silicon carbide is produced. What is the percent yield of this reaction? (find the theoretical amount of SiC using stoichiometry, then calculate percent yield)

Answer : The percent yield of the reaction is, 68.2 %

Explanation : Given,

Mass of = 90.0 g

Mass of = 41.0 g

Molar mass of = 60.08 g/mol

Molar mass of = 40.11 g/mol

First we have to calculate the moles of

Now we have to calculate the moles of

The balanced chemical equation is:

From the reaction, we conclude that

As, 1 mole of react to give 1 mole of

So, 1.498 mole of react to give 1.498 mole of

Now we have to calculate the mass of

Now we have to calculate the percent yield of the reaction.

Experimental yield = 41.0 g

Theoretical yield = 60.08 g

Now put all the given values in this formula, we get:

Therefore, the percent yield of the reaction is, 68.2 %

hloride, what is the mass of calcium in

explanation: