Oxygen gas is collected at a pressure of 1.21 atm in a container which has a volume of 10.0 L. What temperature (in Kelvin) must be maintained on 0.500 moles of this gas in order to maintain this pressure? Round to the nearest whole number (no decimals in your answer).

Answer : The temperature of gas is, 295 K

Explanation :

To calculate the temperature of gas we are using ideal gas equation:

where,

P = Pressure of gas = 1.21 atm

V = Volume of gas = 10.0 L

n = number of moles = 0.500 mole

R = Gas constant =

T = Temperature of gas = ?

Now put all the given values in above equation, we get:

Therefore, the temperature of gas is, 295 K

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.