Chemistry, 07.04.2020 17:37 only1cache
A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10. What is the pOH after 30.5 mL of NaOH is added? The total volume is 25.0 mL + 30.5 mL = 55.5 mL.
Answers: 3
Chemistry, 22.06.2019 19:40, trodgers0202
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Chemistry, 23.06.2019 07:00, jboii11
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Answers: 2
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Answers: 1
A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hyd...
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