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What quantity of gas, in moles, is contained in 22.35L at STP?
me

0.997 mol

Explanation:

Given data:

Number of moles of gas = ?

Volume of gas = 22.35 L

Temperature = standard = 273 K

Pressure = standard = 1 atm

Solution:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values.

n = PV/RT

n = 1 atm ×22.35 L / 0.0821 atm.L/ mol.K  × 273 k

n = 22.35 atm. L / 22.41 atm.L/ mol

n = 0.997 mol

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