A particular deep-sea fish has a swim bladder that can hold a maximum to 0.34 L of gas. It lives at 500m depth. If
the fish's swim bladder currently holds 0.12 L of gas, how high could researchers safely raise it before rupturing
("popping") the swim bladder? (Show your work)

The researcher's can safely raise the fish before reaching the 170 m depth.

Explanation:

Assuming constant temperature, you can use Boyle's law:

         

Where:

p₁ is the pressure at 500 m depth = 50.57 atmp₂ is the unknown pressureV₁ = 0.12 LiterV₂ is the maximum volume that the fish's swim bladder can hold = 0.34 liters

Then, determine p₂:

     

     

From the table, there is a linear relationship between pressure (atm) and water depth (m).

The slope of the linear function is about 0.099:

(50 - 40)/(100-50) = 0.099

The y-intercept is 1.00 (the point 0, 1.00).

Then, the linear function is: Pressure = 1 + 0.099×depth

Now you can find the depth at wich the pressure is 17.85 atm

17.85atm = 1.00atm + 0.099×depthdepth = (17.85 atm - 1.00atm) / 0.099 = 170.2 m ≈ 170 m

Hence, the fish's swimm bladder will ruputure at 170m.

The think of process to make something successful

Molarity is moles of solute over liters of solution. idk if that is what you are talking about, but you can convert moles of solute to grams of solute using dimensional analyzes by using molar mass found on the periodic table.