According to the following equation, Calculate the percentage yield if 550.0 g of toluene (C7H8 )added to an excess of nitric acid (HNO3) provides 305 g of the p-nitrotoluene (C7H7NO2 ) product in a lab experiment.
___C7H8 + ___HNO3  ___C7H7NO2 + ___H2O

37.69 % is the percentage yield if 550.0 g of toluene (C7H8 )added to an excess of nitric acid (HNO3) provides 305 g of the p-nitrotoluene (C7H7NO2 ) product in a lab experiment.

Explanation:

Balanced reaction equation:

C7H8 + ___HNO3  ___C7H7NO2 + ___H2O

data given:

mass of toluene C7H8 = 550 grams (limiting reagent)

mass of nitrotoluene obtained = 305 grams (actual yield)

From the reaction 1 mole of toluene react to form 1 mole of nitrotoluene

atomic mass of nitrotoluene is 137.14 grams/mole

mass of nitrotoluene produced is 137.14 grams

Now the number of moles of nitrotoluene taking part in the reaction is given by:

n =

  = 5.9  moles

hence, form the reaction when 1 mole toluene produced 1 mole of nitrotoluene

5.9 moles will produce 5.9 moles of nitrotoluene

This will give the yield according to the reaction i.e theoretical yield

mass of nitrotoluene = number of  moles x atomic mass of toluene

                                  = 5.9 x 137.14

                                   = 809.12 grams of nitrotoluene (theoretical yield)

Actual yield = 305 grams

formula for percent yield:

percent yield = x 100

                      = x 100

                      = 37.69 % is the yield percent.

37.26% is the correct answer.

Explanation:

maybe the spark is gone, love is a weird emotion and there is a possibility he may have found somebody else.

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation: