How many moles of Ag will be produced from 16g of Cu, assuming AgNO3 is available in excess

Assuming the reaction you are referring to is the following:

AgNO3 + Cu --> Cu(NO3)2 + Ag

First, we should balance the reaction:

2 AgNO3 + Cu --> Cu(NO3)2 + 2 Ag

Now we carry out dimensional analysis, taking into account the molar ratios of different species as given in the balanced reaction and molar masses (which we can look up in the periodic table).

We begin with what we know, which is that we have 16.0 g Cu reacting and work our way toward the quantity that we would like to calculate, namely moles of Ag.

16.0 g Cu x   1 mol Cu    x   2 mol Ag    = 0.504 mol Ag

                     63.5 g Cu       1 mol Cu

i just learnt this recently but i need to look through my notes again

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.