A frisbee is moving at 11 m/s and has 3.6j of energy. how much does it weigh?

0.06 kg

Explanation:

Given data:

Mass of frisbee = ?

Velocity of frisbee  = 11 m/s

Energy of frisbee = 3.6 j

Solution:

K.E = 1/2 mv²

Now we will put  the values in this formula.

3.6 J = 1/2 m(11m/s)²

3.6 j = 0.5 ×121m²/s² × m

3.6 j = 60.5 m²/s² × m

m = 3.6 j/60.5 m²/s²

m= 0.06 j.m⁻².s²

j = Kg.m².s⁻²

m= 0.06 Kg.m².s⁻² .m⁻².s²

m = 0.06 kg

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ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.