Chemistry, 04.04.2020 01:53 deedee363

0.5 moles of any gas is at STP, it will occupy how many LITERS of volume?

Answers: 2

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Answer from: Osmin

500L

Explanation:

No of moles= volume× molarity/1000

No of moles =0.5moles

Volume=?

Molarity of a gas at stp = 1M

Stp means standard temperature and pressure

No of moles = volume ×molarity/1000

Substitute the values

0.5=volume×1/1000

Cross multiply

Volume = 1000×0.5

Volume = 500L

The volume is 500L

Answer from: Quest

en el barco… .. ¿donde comes? yo como en el comedor del barco

¿qué estás comiendo? estoy comiendo arroz con pollo.

¿que hay en la mesa? en la mesa hay muchos platos y un bonito juego de cubiertos.

¿qué haces en el club de la juventud? me junto con mis amigos y jugamos cartas hasta tarde.

¿qué haces en la piscina? en la piscina, nado con mis amigos.

¿estabas dormido? no, estaba leyendo una revista.

¿qué ves en el teatro? en el teatro veo una obra de lope de vega.

a que hora vives hoy. this is illogical because it means what time do you live today? it should be: ¿ a qué hora vienes hoy? hoy vengo a las 4 de la tarde.

¿a qué hora en el verano? en el verano vengo más temprano.

¿qué llevas puesto hoy? hoy llevo puesto un polo y unos pantalones negros.

¿qué te pones cuando vas a la escuela? me pongo un uniforme y zapatos negros.

¿a dónde vas hoy? hoy voy al cine.

¿mañana? en el barco. mañana voy al gimnasio.

Answer from: Quest

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

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