When 38.0 g of N2 is reacted with H2 and 40.12 g of NH3 are produced, what is the percent yield?

52.80 % is the percent yield of the reaction.

Explanation:

Mass of nitrogen gas = 38.0 g

Moles of nitrogen =

According to reaction, 1 moles of nitrogen gas gives 2 moles of ammonia, then 2.235 moles of nitrogen  will give:

 ammonia

Mass of 4.470  moles of ammonia

= 4.470 mol × 17 g/mol = 75.99 g

Theoretical yield of ammonia = 217.8 g

Experimental yield of ammonia = 40.12 g

The percentage yield of reaction:

52.80 % is the percent yield of the reaction.

iron and sleel

make siroeel

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.