What is the empirical formula for a compound that is 54.48% carbon, 13.75% hydrogen, and 31.77 % nitrogen?

Empirical Formula will be for given compound that is 54.48% carbon, 13.75% hydrogen, and 31.77 % nitrogen is .

Explanation:

The formula which gives the simple whole number ratio of the atoms of various elements present in one molecule of the compound is understood as empirical formula. This can be more appropriately understood by solving the given problem as follows:

The % of elements given as:

C = 54.48%

H = 13.75%

N = 31.77%

The atomic mass of elements given as:

C = 12 g

H = 1 g

N = 14 g

Calculating Number of moles as :

Now, we will divide the least number of moles from number of moles of  C, H and N respectively, we will round off the values to an integer value:

For C:  

For H:

For N:

Hence , C , H and N are in the ratio of 2:6:1 , So Empirical Formula will be for given compound that is 54.48% carbon, 13.75% hydrogen, and 31.77 % nitrogen is .

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

i think   the answer is c hope i'm right