7. A sample of argon gas has a volume of 0.43 mL at 24 C. At what temperature in Celsius
will it have a volume of 0.57 mL?

120.55 °C

Explanation:

Given data:

Initial volume of gas = 0.43 mL

Final volume of gas = 0.57 mL

Initial temperature = 24°C (24+273 = 297 k)

Final temperature = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁/V₁  

T₂ = 0.57 mL × 297 K / 0.43 mL

T₂ = 169.29 mL.K / 0.43 mL

T₂ = 393.7 K

Temperature in celsius:

393.7 K - 273.15 = 120.55 °C

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.