Chemistry, 02.04.2020 15:50 robert7248

When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coefficients are:

aluminum oxide (s) + sulfuric acid (aq) > aluminum sulfate (aq) + water (l)

Does a reaction occur when aqueous solutions of ammonium carbonate and chromium(III) nitrate are combined?

Answers: 2

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Answers

Answer from: Nobleufia

1. Al2O3 + 3H2SO4 —> Al2(SO4)3 + 3H2O

The coefficients are: 1, 3, 1, 3

2. Yes, reaction occurs when ammonium carbonate and chromium(III) nitrate are combined.

The balanced equation for the reaction is given below:

3(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3

The coefficients are: 3, 2, 6, 1

Explanation:

1. The word equation is given below:

aluminum oxide(s) + sulfuric acid(aq) -> aluminum sulfate(aq) + water (l)

The above can be written as:

Al2O3 + H2SO4 —> Al2(SO4)3 + H2O

Now we can balance the equation as follow:

There are 3 atoms of SO4 on the right side and 1 atom on the left. It can be balance by putting 3 in front of H2SO4 as shown below:

Al2O3 + 3H2SO4 —> Al2(SO4)3 + H2O

There are 6 atoms of H on the left side and 2 atoms on the right. It can be balance by putting 3 in front of H2O as shown below:

Al2O3 + 3H2SO4 —> Al2(SO4)3 + 3H2O

Now the equation is balanced

The coefficients are: 1, 3, 1, 3

2. Yes, reaction occurs when ammonium carbonate and chromium(III) nitrate are combined.

The equation for the reaction is given below:

(NH4)2CO3 + Cr(NO3)3 —> NH4NO3 + Cr2(CO3)3

We can balance the equation above as follow:

There are 2 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 2 in front of Cr(NO3)3 as shown below:

(NH4)2CO3 + 2Cr(NO3)3 —> NH4NO3 + Cr2(CO3)3

Now, there are 6 atoms of NO3 on the left side and 1 on the right side. It can be balance by putting 6 in front of NH4NO3 as shown below:

(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3

Now, there are 2 atoms of NH4 on the left side and 6 atoms on the right. It can be balance by putting 3 in front of (NH4)2CO3 as shown below:

3(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3

Now the equation is balanced.

The coefficients are: 3, 2, 6, 1

Answer from: Quest

Most smaller stars don't have a radiative zone.

Answer from: Quest

The answer is 1.82 j/g°c

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When the following molecular equation is balanced using the smallest possible integer coefficients,...