2HgO(s) -> 2Hg(l) + O2(g)
Chemistry, 02.04.2020 09:43 jamesnech66
What mass of HgO is required to produce 0.692 mol of O2?
2HgO(s) -> 2Hg(l) + O2(g)
Answers: 2
Chemistry, 21.06.2019 21:40, taysomoneyyy
During trial 2, what allowed you to determine that aluminum was the limiting reactant? check all that apply. all of the copper dissolved. all of the aluminum dissolved. the solution turned clear. the number of grams of copper(ii) chloride used in the reaction was greater than the number of grams of aluminum. the molar ratio of copper(ii) chloride to aluminum was greater than 3: 2, the equation’s molar ratio.
Answers: 2
What mass of HgO is required to produce 0.692 mol of O2?
2HgO(s) -> 2Hg(l) + O2(g)
2HgO(s) -> 2Hg(l) + O2(g)
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