Once the system reaches equilibrium at 675°C additionally H2 is added in the temperature is held constant which statement best describes how this affects the value of K

The given question is incomplete. The complete question is :

Once the system reaches equilibrium at 675°C additionally H2 is added in the temperature is held constant which statement best describes how this affects the value of K

1. The value of K increases because the formation of products is favoured.

2. The value of K decreases because the formation of reactants .

3. The value of K remains unchanged because the temperature remained constant.

4. The value of K cannot be determined as until the equilibrium concentrations are determined.

Answer : The value of K remains unchanged because the temperature remained constant.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K.

K has a definite value for every chemical reaction at a particular temperature.

K is independent of initial concentrations of the reactants.

K changes with the temperature change.

K depends on the nature of the reaction.

Thus as temperature is held constant,  the value of K also remains constant.

in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.